ASP.NET2.0向其它網頁傳遞信息的方法(3)_.Net教程

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      [NextPage]

        < %@ Page language="vb" %>

        < !DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" >

        < html>< head>

        < title>Cross Postback Example 2< /title>

        < /head>< body>

        < script language="vb" runat="server">

        Sub Page_Load()

        If Not (Page.PreviousPage Is Nothing) Then

        If Not (Page.IsCrossPagePostBack) ThenResponse.Write("Name:" CType(PreviousPage.FindControl("txtName"), TextBox).Text "< BR>")Response.Write("E-mail:" CType(PreviousPage.FindControl("txtE-mailAddress"), TextBox).Text "< BR>")

        End If

        End If

        End Sub

        < /script>< /body>< /html>

        

      [NextPage]

        < %@ Page language="vb" %>

        < !DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" >

        < html>< head>

        < title>Cross Postback Example< /title>

        < script language="vb" runat="server">

        Public ReadOnly Property Name

        Get

        Return Me.txtName.Text

        End Get

        End Property

        Public ReadOnly Property E-mailAddress

        Get

        Return Me.txtE-mailAddress.Text

        End Get

        End Property

        < /script>< /head>< body>

        < form id="frmCrossPostback1" method="post" runat="server">

        < asp:Label ID="lblName" runat="server" Text="Name:">< /asp:Label>

        < asp:TextBox ID="txtName" runat="server">< /asp:TextBox>< br />

        < asp:Label ID="lblE-mailAddress" runat="server" Text="E-mail:">< /asp:Label>

        < asp:TextBox ID="txtE-mailAddress" runat="server">< /asp:TextBox>< br />

        < asp:Button ID="btnSubmit" runat="server" Text="Submit" PostBackUrl="CrossPostback2.aspx" />

        < /form>< /body>< /html>

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      AJAX bandwagon是個好去處。它帶給你更快、更高效、更強動態的應用。但它也有自身的缺陷。 初一看,具備一些常識似乎就能避免這些缺陷,在一定程度上,的確如此。但從DHTML起源來看,AJAX應用

      來源:模板無憂//所屬分類:.Net教程/更新時間:2008-08-22
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